The engine power determines its high-speed quality - the more powerful motor, the greater speed can develop the car. Methods for calculating the power of the internal combustion engine and the electric motor will differ. Consider them.
1
Typically, the internal combustion engine power indicators are indicated in specifications. However, over time, the resource is produced and power weakens. To do this, you can check it with the help of specialists and specific equipment.
2
If you want to experiment and calculate the power of the motor yourself, for this you need to know the mass of the machine (from the suggestion), determine the mass of fuel in the tank and the driver. After that, rapidly turn off the car to a speed of 100 kilometers per hour. Fix the time you need to overclock the seconds.
3
To determine the power, you need to apply the following formula: p \u003d 27.78² * m / (2 * t), i.e., the mass of the machine, fuel and the driver multiply by 27.78 in the square, where the last digit is a speed of 100 kilometers per hour, translated in meters per second. The result is divided during overclocking in seconds, multiplied by 2. As a result, we obtain power in watts. If you want to translate into kilowatts, then in the old-kind formula multiply the resulting number per 1000. To get a value in horsepower, the power in kilowatts should be divided by 0.735.
4
If there is a need to measure the power of the electric motor, you need to connect the motor to the current source, the voltage of which you are reliably known. The current strength in amps of each of the windings should be measured by a special tester. Summarize the data obtained. The result multiply to the voltage of the current source. The resulting number is the power of the electric motor.
5
Motor power can also be calculated on dimensions. To do this, determine the diameter and length of the core of the stator in centimeters. Measure the synchronous frequency of rotation of the shaft and the network into which the motor is connected.
6
Next, calculate the constant pole division. The diameter is multiplied by a synchronous frequency and a constant number 3.14. The result is divided by the sum of the frequency of the network and 120. Using the pole division and their number, determine the constant C for the motor. To do this, use the table. Power is calculated by the formula P \u003d C * D² * L * N * 10 ^ -6. The resulting number will determine the power in kilowatts.
It is worth noting that in real life the engine power by and large depends on the revolutions. Therefore, to obtain the maximum speed, the power of the motor is important, and for acceleration - torque.
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S / TT \u003d F / M. Task: Machine M \u003d 1160 kg. S \u003d 250 m. T \u003d 18 seconds. KPD DVS \u003d 16% ("Zhiguli", "Moskvich") n \u003d? Solution: 250: 324 \u003d F: 1160. n \u003d 900 kg / s. This is 12 hp At 100% efficiency !!! At 16% power \u003d 12 * 6,25 \u003d 75 hp (This is the maximum power at Max. Rapid acceleration).
S, T, M, V can be measured. Task: Find F, Efficiency (DVS) ... Newton in the formula s \u003d ATT / 2- error! Correctly: S \u003d ATT (no / 2) Then S / TT \u003d F / M. And so - under any conditions! Search "Acceleration" - meaningless. Increased f. By the way: "A" -skore is the energy causing a change in the speed-f / m. a \u003d S / TT \u003d V Average !!! / T \u003d F / M \u003d (V + V) / 2T. V Average (!) \u003d AT. V finite \u003d 2AT (if V start \u003d 0). At the falling "apple ..." V beginning. \u003d 0, v con. \u003d 9.8 m / s. V Wed \u003d 4.9 m / s. \u003d AT. a \u003d 4.9 / 1 \u003d 4.9 m / s. (and not 9.8 .. !!!) Problem: stone weighing 30 kg. moved to 50 m. per minute. What is the power? Solution: 50/3600 \u003d F / 30. F \u003d 0.42 kg. M / s.
Without efficiency, you can not do. Finding "clean" power (16%) and multiply by 6.25. S / TT \u003d F / M. S, T, M can be measured. Let: ... S \u003d 300 m., T \u003d 20 seconds. M \u003d 1400 kg. Solution: 300/400 \u003d f / 1400 f \u003d 1050 kg / s. This \u003d 14 hp 14 * 6,25 \u003d 87.5 hp
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S / TT \u003d F / M. Task: Machine M \u003d 1160 kg. S \u003d 250 m. T \u003d 18 seconds. KPD DVS \u003d 16% ("Zhiguli", "Moskvich") n \u003d? Solution: 250: 324 \u003d F: 1160. n \u003d 900 kg / s. This is 12 hp At 100% efficiency !!!
At 16% power \u003d 12 * 6,25 \u003d 75 hp (This is the maximum power at Max. Rapid acceleration).
S, T, M, V can be measured. Task: Find F, Efficiency (DVS) ...
Newton in the formula s \u003d ATT / 2- error! Correctly: S \u003d ATT (no / 2)
Then S / TT \u003d F / M. And so - under any conditions! Search "Acceleration" - meaningless. Increased f.
By the way: "A" -skore is the energy causing a change in the speed-f / m. a \u003d S / TT \u003d V Average !!! / T \u003d F / M \u003d (V + V) / 2T.
V Average (!) \u003d AT. V finite \u003d 2AT (if V start \u003d 0). At the falling "apple ..." V beginning. \u003d 0, v con. \u003d 9.8 m / s. V Wed \u003d 4.9 m / s. \u003d AT. a \u003d 4.9 / 1 \u003d 4.9 m / s. (and not 9.8 .. !!!)
Problem: stone weighing 30 kg. moved to 50 m. per minute. What is the power? Solution: 50/3600 \u003d F / 30. F \u003d 0.42 kg. M / s.
Without efficiency, you can not do. Finding "clean" power (16%) and multiply by 6.25.
S / TT \u003d F / M. S, T, M can be measured. Let: ... S \u003d 300 m., T \u003d 20 seconds. M \u003d 1400 kg.
Solution: 300/400 \u003d f / 1400 f \u003d 1050 kg / s. This \u003d 14 hp
14 * 6,25 \u003d 87.5 hp