How to decompose the square three-stakes on multipliers

My article will help you understand the principle of decomposition of a square equation with three unknown to members.

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The main method of decomposition of a square equation with three unknown members

Square equation with three unknowns refer to the equation of the type AX ²+ BX + s.
To decompose the square equation with three unknown, the general denominator will be put up for brackets.

We have a square three-half x ²+ 5x + 6. And we need to decompose it on multipliers, that is, get two brackets. So what will be in brackets?
To do this, look at the coefficients. This square three decreases three coefficients: 1, 5 and 6. We are interested in the second and third coefficients.
We need to find two such numbers that give 5 in the amount, that is, the second ratio, and the multiplication give 6. What are these numbers?
Well, what numbers in principle give 6 when multiplying. These numbers include: 1) 6 and 1, 2) 2 and 3.
The amount 6 and 1 gives in the end 7, which is not equal to 5, so this option is not suitable for us.
But the amount 2 and 3 suits us, because in the end gives 5, that is, the result of the second coefficient. When multiplying 2 and 3, in the end, give the result of the third coefficient.
As a result, our decomposition will look like (x + 2) (x + 3).